y^2+16y+20=0

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Solution for y^2+16y+20=0 equation:


Simplifying
y2 + 16y + 20 = 0

Reorder the terms:
20 + 16y + y2 = 0

Solving
20 + 16y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + 16y + -20 + y2 = 0 + -20

Reorder the terms:
20 + -20 + 16y + y2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 16y + y2 = 0 + -20
16y + y2 = 0 + -20

Combine like terms: 0 + -20 = -20
16y + y2 = -20

The y term is 16y.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16y + 64 + y2 = -20 + 64

Reorder the terms:
64 + 16y + y2 = -20 + 64

Combine like terms: -20 + 64 = 44
64 + 16y + y2 = 44

Factor a perfect square on the left side:
(y + 8)(y + 8) = 44

Calculate the square root of the right side: 6.633249581

Break this problem into two subproblems by setting 
(y + 8) equal to 6.633249581 and -6.633249581.

Subproblem 1

y + 8 = 6.633249581 Simplifying y + 8 = 6.633249581 Reorder the terms: 8 + y = 6.633249581 Solving 8 + y = 6.633249581 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + y = 6.633249581 + -8 Combine like terms: 8 + -8 = 0 0 + y = 6.633249581 + -8 y = 6.633249581 + -8 Combine like terms: 6.633249581 + -8 = -1.366750419 y = -1.366750419 Simplifying y = -1.366750419

Subproblem 2

y + 8 = -6.633249581 Simplifying y + 8 = -6.633249581 Reorder the terms: 8 + y = -6.633249581 Solving 8 + y = -6.633249581 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + y = -6.633249581 + -8 Combine like terms: 8 + -8 = 0 0 + y = -6.633249581 + -8 y = -6.633249581 + -8 Combine like terms: -6.633249581 + -8 = -14.633249581 y = -14.633249581 Simplifying y = -14.633249581

Solution

The solution to the problem is based on the solutions from the subproblems. y = {-1.366750419, -14.633249581}

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